9AD^2=7AB^2 | Homework Help | myCBSEguide
Given : An equilateral triangle ABC such that To Prove : 9AD 2 = 7AB 2. Const: Draw AE ⊥ BC. Proof: In right triangles ABE and ACE, we have. AE = AE [common] ∠AEB = ∠AEC [90°] and AB = AC. [∆ABC is an equilateral] Therefore, by using RHS congruent condition. BE = CE [by CPCT]
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What is 3ab - 9ab plus 7ab? - Answers
What is the area of a rectangle if the width is 3ab cm and length is 7ab cm? 21a2b2 square cm. How much is 12ab plus 3ab? 12ab+3ab=15ab. 12a2b plus 8a-5a2b plus 2ab - …
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If a² + b² = 7ab, prove that log [⅓(a+b)] = ½ [log a + log ...
Answer (1 of 11): Remember that: {(a+b)}^2=a^2+2ab+b^2 and log{(a)}+log{(b)}=log{(ab)} So, a^2+b^2=7ab Adding 2ab on both sides : a^2+b^2+2ab=7ab+2ab {(a+b)}^2=9ab ...